189 字
1 分钟
23. Merge k Sorted Lists
2021-09-14
2023-12-10

Problem#

https://leetcode-cn.com/problems/merge-k-sorted-lists/

Soluitions#

/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode mergeKLists(ListNode[] lists) {
if(lists.length == 0) {
return null;
}
// if(lists.length == 1) {
// return lists[0];
// }
for(int i = 1; i < lists.length; i++) {
lists[i] = merge2Lists(lists[i-1], lists[i]);
}
return lists[lists.length - 1];
}
public ListNode merge2Lists(ListNode l1, ListNode l2) {
ListNode newList = new ListNode();
ListNode curr = newList;
while(l1 != null && l2 != null) {
if(l1.val < l2.val) {
curr.next = l1;
l1 = l1.next;
} else {
curr.next = l2;
l2 = l2.next;
}
curr = curr.next;
}
if(l1 == null) {
curr.next = l2;
}
if(l2 == null) {
curr.next = l1;
}
return newList.next;
}
}

暴力解决

  1. 解决合并2个顺序链表
  2. 循环调用直到合并完成整个list的有序链表

Reference#

23. Merge k Sorted Lists
https://static.next.liqimore.com/2021/leetcode-merge-k-sorted-lists
作者
Ricky Li
发布于
2021-09-14
许可协议
CC BY-NC-SA 4.0
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